(2x-3)(x^2-4x+5)=

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Solution for (2x-3)(x^2-4x+5)= equation: 


Simplifying
(2x + -3)(x2 + -4x + 5) = 0

Reorder the terms:
(-3 + 2x)(x2 + -4x + 5) = 0

Reorder the terms:
(-3 + 2x)(5 + -4x + x2) = 0

Multiply (-3 + 2x) * (5 + -4x + x2)
(-3(5 + -4x + x2) + 2x * (5 + -4x + x2)) = 0
((5 * -3 + -4x * -3 + x2 * -3) + 2x * (5 + -4x + x2)) = 0
((-15 + 12x + -3x2) + 2x * (5 + -4x + x2)) = 0
(-15 + 12x + -3x2 + (5 * 2x + -4x * 2x + x2 * 2x)) = 0
(-15 + 12x + -3x2 + (10x + -8x2 + 2x3)) = 0

Reorder the terms:
(-15 + 12x + 10x + -3x2 + -8x2 + 2x3) = 0

Combine like terms: 12x + 10x = 22x
(-15 + 22x + -3x2 + -8x2 + 2x3) = 0

Combine like terms: -3x2 + -8x2 = -11x2
(-15 + 22x + -11x2 + 2x3) = 0

Solving
-15 + 22x + -11x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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